What is the solution for y^{''}+pi^2y=2 ?

The solution for y^{''}+pi^2y=2 is y=c_{1}cos(pit)+c_{2}sin(pit)+2/(pi^2)

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y^{''}+pi^2y=2

y^{^{''}} + π^{2} y = 2

y = c_{1} cos (π t) + c_{2} sin (π t) + \frac{2}{π ^{2}}

Solution steps

y^{''} (t) + π^{2} y = 2

Solve linear ODE:

y = c_{1} cos (π t) + c_{2} sin (π t) + \frac{2}{π ^{2}}

y = c_{1} cos (π t) + c_{2} sin (π t) + \frac{2}{π ^{2}}

2 x^{3} - 2 x^{2} + 12

x^{\frac{3}{8}}

x \to 0 lim (- 2 - x)

(x^{2} + 1) y^{^{'}} + 3 x (y - 1) = 0, y (0) = 3

\frac{d}{d x} (x^{2} - 6 x + 8)

What is the solution for y^{''}+pi^2y=2 ?
The solution for y^{''}+pi^2y=2 is y=c_{1}cos(pit)+c_{2}sin(pit)+2/(pi^2)