What is the derivative of x^2-6x+8 ?

The derivative of x^2-6x+8 is 2x-6

What is the first derivative of x^2-6x+8 ?

The first derivative of x^2-6x+8 is 2x-6

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\frac{d}{d x} (x^{2} - 6 x + 8)

2 x - 6

Solution steps

\frac{d}{d x} (x^{2} - 6 x + 8)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (6 x) + \frac{d}{d x} (8)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (6 x) = 6

\frac{d}{d x} (8) = 0

= 2 x - 6 + 0

Simplify

= 2 x - 6

\frac{2 x}{1 + x ^{2}}

x \to 0 - lim (1)

n = 1 \sum \infty ln (n + 1)

f (x) = 8 x^{2}

What is the derivative of x^2-6x+8 ?
The derivative of x^2-6x+8 is 2x-6
What is the first derivative of x^2-6x+8 ?
The first derivative of x^2-6x+8 is 2x-6