What is area x=y^2+3,x=y,y=-1,y=1 ?

The answer to area x=y^2+3,x=y,y=-1,y=1 is No Solution

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area x=y^2+3,x=y,y=-1,y=1

area

x = y^{2} + 3, x = y, y = - 1, y = 1

No Solution

Solution steps

Isolate

y

for

x = y^{2} + 3 : y = x - 3, y = - x - 3

Isolate

y

for

x = y : y = x

f_{1} (x) = x - 3

f_{2} (x) = - x - 3

To find the intersection points solve

f_{i} (x) = f_{j} (x)

x - 3 = - x - 3 : x = 3

x - 3 = x :

No Solution for

x \in R

x - 3 = - 1 :

No Solution for

x \in R

x - 3 = 1 : x = 4

- x - 3 = x :

No Solution for

x \in R

- x - 3 = - 1 : x = 4

- x - 3 = 1 :

No Solution for

x \in R

x = - 1 : x = - 1

x = 1 : x = 1

- 1 = 1 :

False

Curves not bounded

= No Solution

n = 9 \sum \infty \frac{1}{n ( n - 1 )}

x^{2} - 2 x

\int tan (\frac{x}{4}) d x

\frac{a}{1 - b x}

\frac{d y}{d x} - 5 y = x^{2}

What is area x=y^2+3,x=y,y=-1,y=1 ?
The answer to area x=y^2+3,x=y,y=-1,y=1 is No Solution