What is the integral from-infinity to 0 of 1/(4-6x) ?

The integral from-infinity to 0 of 1/(4-6x) is diverges

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integral from-infinity to 0 of 1/(4-6x)

\int_{- \infty}^{0} \frac{1}{4 - 6 x} d x

diverges

Solution steps

\int_{- \infty}^{0} \frac{1}{4 - 6 x} d x

Compute the indefinite integral:

\int \frac{1}{4 - 6 x} d x = - \frac{1}{6} ln ∣ 4 - 6 x ∣ + C

Compute the boundaries:

\int_{- \infty}^{0} \frac{1}{4 - 6 x} d x =

diverges

= diverges

e^{c s c (x)}

\int \frac{1}{t ^{\frac{1}{2}}} d t

3 x + y^{2} = 13, x = 4 y

x = - y^{2} + 4, x = - 3 y

y^{3} d x + 2 (x^{3} - x y^{2}) d y = 0

What is the integral from-infinity to 0 of 1/(4-6x) ?
The integral from-infinity to 0 of 1/(4-6x) is diverges