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Popular >

y^{''}-16y=0

Solution

y^{^{''}} - 16 y = 0

Solution

y = c_{1} e^{4 t} + c_{2} e^{- 4 t}

Solution steps

y^{''} (t) - 16 y = 0

Solve linear ODE:

y = c_{1} e^{4 t} + c_{2} e^{- 4 t}

y = c_{1} e^{4 t} + c_{2} e^{- 4 t}

Popular Examples

integral of (2x^2)/(2x^2+1)

\int \frac{2 x ^{2}}{2 x ^{2} + 1} d x

integral of x(2x^2-1)^4

\int x (2 x^{2} - 1)^{4} d x

derivative of 2x+y

\frac{d}{d x} (2 x + y)

d/(dt)(t^2e^{-t})

\frac{d}{d t} (t^{2} e^{- t})

x*y^2*y^'=x^3+y^3

x \cdot y^{2} \cdot y^{^{'}} = x^{3} + y^{3}

Frequently Asked Questions (FAQ)

What is the solution for y^{''}-16y=0 ?
The solution for y^{''}-16y=0 is y=c_{1}e^{4t}+c_{2}e^{-4t}