What is the derivative of y=6e^x+4/(\sqrt[3]{x)} ?

The derivative of y=6e^x+4/(\sqrt[3]{x)} is 6e^x-4/(3x^{4/3)}

What is the first derivative of y=6e^x+4/(\sqrt[3]{x)} ?

The first derivative of y=6e^x+4/(\sqrt[3]{x)} is 6e^x-4/(3x^{4/3)}

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derivative of

y = 6 e^{x} + \frac{4}{3 x}

6 e^{x} - \frac{4}{3 x ^{\frac{4}{3}}}

Solution steps

\frac{d}{d x} (6 e^{x} + \frac{4}{3 x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (6 e^{x}) + \frac{d}{d x} (\frac{4}{3 x})

\frac{d}{d x} (6 e^{x}) = 6 e^{x}

\frac{d}{d x} (\frac{4}{3 x}) = - \frac{4}{3 x ^{\frac{4}{3}}}

= 6 e^{x} - \frac{4}{3 x ^{\frac{4}{3}}}

\frac{d}{d x} (e^{- 12 x})

\int (1 - x - y)^{3} d y

(3, - 5), (5, - 5)

y^{^{'}} + 3 x^{2} y = x e^{- x^{3}}

\frac{d}{d x} (lo g_{e} (\frac{4 x ^{2} - 9}{2 x - 3}))

What is the derivative of y=6e^x+4/(\sqrt[3]{x)} ?
The derivative of y=6e^x+4/(\sqrt[3]{x)} is 6e^x-4/(3x^{4/3)}
What is the first derivative of y=6e^x+4/(\sqrt[3]{x)} ?
The first derivative of y=6e^x+4/(\sqrt[3]{x)} is 6e^x-4/(3x^{4/3)}