What is area y=1+2sqrt(x),y=(3+x)/3 ?

The answer to area y=1+2sqrt(x),y=(3+x)/3 is 72

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area y=1+2sqrt(x),y=(3+x)/3

area

y = 1 + 2 x, y = \frac{3 + x}{3}

72

Solution steps

Apply the area formula:

\int_{0}^{36} 1 + 2 x - \frac{3 + x}{3} d x

Solve

\int_{0}^{36} 1 + 2 x - \frac{3 + x}{3} d x : 72

The area is:

= 72

x, \frac{x}{2}

y = \frac{1}{x}, y = \frac{1}{x ^{2}}, x = 4

x (x^{2} - 10 x + 30), x^{2}, 0, 5

\frac{d}{d x} (\frac{- sin ( x )}{cos ( x )})

f (x) = 4 x^{3} - 14 x^{2} + 49 x + 6

What is area y=1+2sqrt(x),y=(3+x)/3 ?
The answer to area y=1+2sqrt(x),y=(3+x)/3 is 72