What is the derivative of 1+cot(x) ?

The derivative of 1+cot(x) is -csc^2(x)

What is the first derivative of 1+cot(x) ?

The first derivative of 1+cot(x) is -csc^2(x)

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\frac{d}{d x} (1 + cot (x))

- csc^{2} (x)

Solution steps

\frac{d}{d x} (1 + cot (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) + \frac{d}{d x} (cot (x))

\frac{d}{d x} (1) = 0

\frac{d}{d x} (cot (x)) = - csc^{2} (x)

= 0 - csc^{2} (x)

Simplify

= - csc^{2} (x)

x \to 1 lim (\frac{1 - \frac{1}{x}}{x - 1})

\frac{d}{d x} (\frac{cos ( x - y )}{sin ( y - x )})

\frac{d}{d x} (2 x^{4} - 8 x + 3)

\frac{d}{d x} ((x^{2})^{- 1})

\frac{\partial}{\partial x} (\frac{y}{1 + x ^{2} + y ^{2}})

What is the derivative of 1+cot(x) ?
The derivative of 1+cot(x) is -csc^2(x)
What is the first derivative of 1+cot(x) ?
The first derivative of 1+cot(x) is -csc^2(x)