What is the solution for (x^2+y)dx+(x+e^y)dy=0 ?

The solution for (x^2+y)dx+(x+e^y)dy=0 is y=-\W((e^{(-x^3+3c_{1})/(3x)})/x)+(3c_{1}-x^3)/(3x)

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(x^2+y)dx+(x+e^y)dy=0

(x^{2} + y) d x + (x + e^{y}) d y = 0

y = - W \frac{e ^{\frac{- x ^{3} + 3 c _{1}}{3 x}}}{x} + \frac{3 c _{1} - x ^{3}}{3 x}

Solution steps

(x^{2} + y) d x + (x + e^{y}) d y = 0

Solve exact ODE:

y = - W \frac{e ^{\frac{- x ^{3} + 3 c _{1}}{3 x}}}{x} + \frac{3 c _{1} - x ^{3}}{3 x}

y = - W \frac{e ^{\frac{- x ^{3} + 3 c _{1}}{3 x}}}{x} + \frac{3 c _{1} - x ^{3}}{3 x}

\int_{0}^{l n (2)} \frac{2}{e ^{x} + 3} d x

2 t e^{- t}

(1, - 4), (4, - 5)

\int cos (π)

x \to 3 + lim (\frac{1}{x ^{2} - 9})

What is the solution for (x^2+y)dx+(x+e^y)dy=0 ?
The solution for (x^2+y)dx+(x+e^y)dy=0 is y=-\W((e^{(-x^3+3c_{1})/(3x)})/x)+(3c_{1}-x^3)/(3x)