What is the limit as x approaches 3+of 1/(x^2-9) ?

The limit as x approaches 3+of 1/(x^2-9) is infinity

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 3+of 1/(x^2-9)

x \to 3 + lim (\frac{1}{x ^{2} - 9})

\infty

Solution steps

x \to 3 + lim (\frac{1}{x ^{2} - 9})

For

x

approaching

3

from the right

, x > 3 \Rightarrow x^{2} - 9 > 0

The denominator is a positive quantity approaching 0 from the right

= \infty

\frac{d}{d x} (\frac{3 x}{( x ^{2} + 1 ) ^{\frac{3}{5}}})

(x^{2} - 2 x + 4), 2

\int \frac{1}{x ^{2} 4 x ^{2} - 1} d x

x \frac{d y}{d x} = y + (x^{2} + y^{2})^{\frac{1}{2}}

f (x) = 2 x^{2} + x - 1, at a = - 2

What is the limit as x approaches 3+of 1/(x^2-9) ?
The limit as x approaches 3+of 1/(x^2-9) is infinity