What is taylor (x^2-2x+4),2 ?

The answer to taylor (x^2-2x+4),2 is 4+2(x-2)+(x-2)^2

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taylor (x^2-2x+4),2

taylor

(x^{2} - 2 x + 4), 2

4 + 2 (x - 2) + (x - 2)^{2}

Solution steps

Apply the Taylor Formula

= 4 + \frac{\frac{d}{d x} ( x ^{2} - 2 x + 4 ) ( 2 )}{1 !} (x - 2) + \frac{\frac{d ^{2}}{d x ^{2}} ( x ^{2} - 2 x + 4 ) ( 2 )}{2 !} (x - 2)^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( x ^{2} - 2 x + 4 ) ( 2 )}{3 !} (x - 2)^{3} + \dots

Evaluate Derivatives

= 4 + \frac{2}{1 !} (x - 2) + \frac{2}{2 !} (x - 2)^{2} + \frac{0}{3 !} (x - 2)^{3} + \frac{0}{4 !} (x - 2)^{4} + \frac{0}{5 !} (x - 2)^{5} + \frac{0}{6 !} (x - 2)^{6} + \frac{0}{7 !} (x - 2)^{7} + \frac{0}{8 !} (x - 2)^{8} + \frac{0}{9 !} (x - 2)^{9} + \frac{0}{10 !} (x - 2)^{10}

Refine

= 4 + 2 (x - 2) + (x - 2)^{2}

\int \frac{1}{x ^{2} 4 x ^{2} - 1} d x

x \frac{d y}{d x} = y + (x^{2} + y^{2})^{\frac{1}{2}}

f (x) = 2 x^{2} + x - 1, at a = - 2

\int e^{x} x cos (x) d x

f (x) = 1 - 2 x

What is taylor (x^2-2x+4),2 ?
The answer to taylor (x^2-2x+4),2 is 4+2(x-2)+(x-2)^2