What is the tangent of y=6ln(x^2),(e,12) ?

The tangent of y=6ln(x^2),(e,12) is y=(12)/e x

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tangent of y=6ln(x^2),(e,12)

tangent of

y = 6 ln (x^{2}), (e, 12)

y = \frac{12}{e} x

Solution steps

Find the slope of

y = 6 ln (x^{2}) : \frac{d y}{d x} = \frac{12}{x}

Compute the slope of

y = 6 ln (x^{2})

(e, 12) : m = \frac{12}{e}

Find the line with slope m=

\frac{12}{e}

and passing through

(e, 12) : y = \frac{12}{e} x

y = \frac{12}{e} x

f (x) = e^{x} sin (x), (0, 0)

y = \frac{3 + 7 x - 8 x}{x}

(x^{2} e^{x + 3})^{^{'}}

y^{^{'}} = - 3 y + e^{- 2 x}, y (0) = 0

f (x) = \frac{2}{1 + x ^{2}}, h (x) = x^{2}

What is the tangent of y=6ln(x^2),(e,12) ?
The tangent of y=6ln(x^2),(e,12) is y=(12)/e x