What is area f(x)= 2/(1+x^2),h(x)=x^2 ?

The answer to area f(x)= 2/(1+x^2),h(x)=x^2 is pi-2/3

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area f(x)= 2/(1+x^2),h(x)=x^2

area

f (x) = \frac{2}{1 + x ^{2}}, h (x) = x^{2}

π - \frac{2}{3}

Decimal Notation

2.47492 \dots

Solution steps

Apply the area formula:

\int_{- 1}^{1} \frac{2}{1 + x ^{2}} - x^{2} d x

Solve

\int_{- 1}^{1} \frac{2}{1 + x ^{2}} - x^{2} d x : π - \frac{2}{3}

The area is:

= π - \frac{2}{3}

\frac{d y}{d x} = (\frac{( x y ) ^{2}}{8} + y^{2})

\frac{d ^{2}}{d x ^{2}} (ln (x))

y^{^{''}} + 4.5 y^{^{'}} = 0

\int x + 4 - \frac{4}{x} d x

\frac{2 t + t}{t + 3}

What is area f(x)= 2/(1+x^2),h(x)=x^2 ?
The answer to area f(x)= 2/(1+x^2),h(x)=x^2 is pi-2/3