What is the derivative of f(x)=4x^2-x^3 ?

The derivative of f(x)=4x^2-x^3 is 8x-3x^2

What is the first derivative of f(x)=4x^2-x^3 ?

The first derivative of f(x)=4x^2-x^3 is 8x-3x^2

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derivative of

f (x) = 4 x^{2} - x^{3}

8 x - 3 x^{2}

Solution steps

\frac{d}{d x} (4 x^{2} - x^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{2}) - \frac{d}{d x} (x^{3})

\frac{d}{d x} (4 x^{2}) = 8 x

\frac{d}{d x} (x^{3}) = 3 x^{2}

= 8 x - 3 x^{2}

\frac{\partial}{\partial z} (\frac{x}{y + 2 z})

x^{^{''}} + 4 x = 0

n = 1 \sum \infty \frac{1}{n + 1 ^{- n}}

5 y^{^{''}} + 15 y^{^{'}} - 20 y = 0

\int (x^{2} - x + 1) d x

What is the derivative of f(x)=4x^2-x^3 ?
The derivative of f(x)=4x^2-x^3 is 8x-3x^2
What is the first derivative of f(x)=4x^2-x^3 ?
The first derivative of f(x)=4x^2-x^3 is 8x-3x^2