What is the derivative of 1/(-x^2) ?

The derivative of 1/(-x^2) is 2/(x^3)

What is the first derivative of 1/(-x^2) ?

The first derivative of 1/(-x^2) is 2/(x^3)

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\frac{d}{d x} (\frac{1}{- x ^{2}})

\frac{2}{x ^{3}}

Solution steps

\frac{d}{d x} (\frac{1}{- x ^{2}})

Simplify

\frac{1}{- x ^{2}} : - \frac{1}{x ^{2}}

= \frac{d}{d x} (- \frac{1}{x ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{d}{d x} (\frac{1}{x ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= - \frac{d}{d x} (x^{- 2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - (- 2 x^{- 2 - 1})

Simplify

- (- 2 x^{- 2 - 1}) : \frac{2}{x ^{3}}

= \frac{2}{x ^{3}}

\frac{d y}{d x} = x + 2 y, y (0) = 6

x \to 0 lim (\frac{π x ^{2} + 2}{x})

\frac{\partial}{\partial x} (ln ∣ x ∣)

x \to 0 lim (3 x ln (x))

x \to 3 lim (8 x^{2} + 9)

What is the derivative of 1/(-x^2) ?
The derivative of 1/(-x^2) is 2/(x^3)
What is the first derivative of 1/(-x^2) ?
The first derivative of 1/(-x^2) is 2/(x^3)