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Popular >

y^'=-y-2x,y(0)=1

Solution

y^{^{'}} = - y - 2 x, y (0) = 1

Solution

y = - 2 (x - 1) - \frac{1}{e ^{x}}

Solution steps

y^{'} (x) = - y - 2 x

Solve linear ODE:

y = - 2 (x - 1) - \frac{1}{e ^{x}}

y = - 2 (x - 1) - \frac{1}{e ^{x}}

Popular Examples

(dy)/(dx)+4xy^3=0

\frac{d y}{d x} + 4 x y^{3} = 0

derivative of f(x)=(-16x^2+36)^2 derivative of

f (x) = (- 16 x^{2} + 36)^{2}

derivative of arctan(tanh(x))

\frac{d}{d x} (arctan (tanh (x)))

integral of (2x^3+1)/(x^2+x-6)

\int \frac{2 x ^{3} + 1}{x ^{2} + x - 6} d x

integral of 1/(sqrt(2x^2-4x+6))

\int \frac{1}{2 x ^{2} - 4 x + 6} d x

Frequently Asked Questions (FAQ)

What is the solution for y^'=-y-2x,y(0)=1 ?
The solution for y^'=-y-2x,y(0)=1 is y=-2(x-1)-1/(e^x)