What is the integral from 0 to 1 of (73)/(x^5) ?

The integral from 0 to 1 of (73)/(x^5) is diverges

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integral from 0 to 1 of (73)/(x^5)

\int_{0}^{1} \frac{73}{x ^{5}} d x

diverges

Solution steps

\int_{0}^{1} \frac{73}{x ^{5}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 73 \cdot \int_{0}^{1} \frac{1}{x ^{5}} d x

Apply the Power Rule

: [- \frac{1}{4 x ^{4}}]_{0}^{1}

= 73 [- \frac{1}{4 x ^{4}}]_{0}^{1}

Compute the boundaries:

diverges

= diverges

x \to - 1 lim (\frac{in x}{x - 1})

\frac{d y}{d x} = 2 x y^{2} + 72 x

f (x) = 4 x^{2} + 3 x

\int x^{3} x^{2} + 25 d x

\frac{d y}{d x} = \frac{y}{y - x}

What is the integral from 0 to 1 of (73)/(x^5) ?
The integral from 0 to 1 of (73)/(x^5) is diverges