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Popular >

area x=y^2-4y,x=0

Solution

area

x = y^{2} - 4 y, x = 0

Solution

\frac{32}{3}

+1

Decimal Notation

10.66666 \dots

Solution steps

Isolate

y

for

x = y^{2} - 4 y : y = 2 + x + 4, y = 2 - x + 4

Apply the area formula:

\int_{- 4}^{0} 2 + x + 4 - (2 - x + 4) d x

Solve

\int_{- 4}^{0} 2 + x + 4 - (2 - x + 4) d x : \frac{32}{3}

The area is:

= \frac{32}{3}

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Frequently Asked Questions (FAQ)

What is area x=y^2-4y,x=0 ?
The answer to area x=y^2-4y,x=0 is 32/3