What is the solution for (dy)/(dt)+(4y)/(200+3t)=8 ?

The solution for (dy)/(dt)+(4y)/(200+3t)=8 is

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(dy)/(dt)+(4y)/(200+3t)=8

\frac{d y}{d t} + \frac{4 y}{200 + 3 t} = 8

y = \frac{8 ( 21 t ( 200 + 3 t ) ^{\frac{4}{3}} - 4 ( ( 3 t + 200 ) ^{\frac{7}{3}} - 350 ( 3 t + 200 ) ^{\frac{4}{3}} ) )}{21 ( 200 + 3 t ) ^{\frac{4}{3}}} + \frac{c _{1}}{( 200 + 3 t ) ^{\frac{4}{3}}}

Solution steps

\frac{d y}{d t} + \frac{4 y}{200 + 3 t} = 8

Solve linear ODE:

y = \frac{8 ( 21 t ( 200 + 3 t ) ^{\frac{4}{3}} - 4 ( ( 3 t + 200 ) ^{\frac{7}{3}} - 350 ( 3 t + 200 ) ^{\frac{4}{3}} ) )}{21 ( 200 + 3 t ) ^{\frac{4}{3}}} + \frac{c _{1}}{( 200 + 3 t ) ^{\frac{4}{3}}}

y = \frac{8 ( 21 t ( 200 + 3 t ) ^{\frac{4}{3}} - 4 ( ( 3 t + 200 ) ^{\frac{7}{3}} - 350 ( 3 t + 200 ) ^{\frac{4}{3}} ) )}{21 ( 200 + 3 t ) ^{\frac{4}{3}}} + \frac{c _{1}}{( 200 + 3 t ) ^{\frac{4}{3}}}

f (x) = 2 sec^{2} (x) tan (x)

\int \frac{21}{( x ^{2} - 1 ) ^{2}} d x

\frac{d}{d t} (e^{- 2 t} y (t))

2 sin (2 x)

f (x) = 3 x + 7

What is the solution for (dy)/(dt)+(4y)/(200+3t)=8 ?
The solution for (dy)/(dt)+(4y)/(200+3t)=8 is