What is inverse oflaplace (e^{-4s})/s ?

The answer to inverse oflaplace (e^{-4s})/s is \H(t-4)

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inverse oflaplace (e^{-4s})/s

inverse laplace

\frac{e ^{- 4 s}}{s}

H (t - 4)

Solution steps

L^{- 1} {\frac{e ^{- 4 s}}{s}}

Apply inverse transform rule:

L^{- 1} {F (s)} = f (t)

then

L^{- 1} {e^{- a s} F (s)} = H (t - a) f (t - a)

Where

H (t)

is Heaviside step function

= H (t - 4) L^{- 1} {\frac{1}{s}} (t - 4)

L^{- 1} {\frac{1}{s}} : H (t)

= H (t - 4) H (t - 4)

= H (t - 4)

\int_{0}^{\frac{5}{4}} \frac{1}{25 + 16 x ^{2}} d x

\frac{d}{d x} (y ln (x))

y = \frac{4 ln ( 3 x )}{5 + 2 x}

6 cos (t), at t = - \frac{π}{4}

2 s + 1

What is inverse oflaplace (e^{-4s})/s ?
The answer to inverse oflaplace (e^{-4s})/s is \H(t-4)