What is the derivative of sqrt(16-x) ?

The derivative of sqrt(16-x) is -1/(2sqrt(16-x))

What is the first derivative of sqrt(16-x) ?

The first derivative of sqrt(16-x) is -1/(2sqrt(16-x))

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\frac{d}{d x} (16 - x)

- \frac{1}{2 16 - x}

Solution steps

\frac{d}{d x} (16 - x)

Apply the chain rule:

\frac{1}{2 16 - x} \frac{d}{d x} (16 - x)

= \frac{1}{2 16 - x} \frac{d}{d x} (16 - x)

\frac{d}{d x} (16 - x) = - 1

= \frac{1}{2 16 - x} (- 1)

Simplify

= - \frac{1}{2 16 - x}

x \to 0 lim (\frac{cos ( x - 1 )}{x})

\frac{d}{d x} (x^{2} + 8 x - 5)

x^{\frac{11}{12}}

y^{2} = x, y = - x + 2

e^{- 4 t} + 5

What is the derivative of sqrt(16-x) ?
The derivative of sqrt(16-x) is -1/(2sqrt(16-x))
What is the first derivative of sqrt(16-x) ?
The first derivative of sqrt(16-x) is -1/(2sqrt(16-x))