What is the tangent of y=x^2-5x+5(0.5) ?

The tangent of y=x^2-5x+5(0.5) is y=(2a_{0}-5)x-a_{0}^2+2.5

Popular >

tangent of y=x^2-5x+5(0.5)

tangent of

y = x^{2} - 5 x + 5 (0.5)

y = (2 a_{0} - 5) x - a_{0}^{2} + 2.5

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, a_{0}^{2} - 5 a_{0} + 2.5)

Find the slope of

y = x^{2} - 5 x + 5 \cdot 0.5 : \frac{d y}{d x} = 2 x - 5

Compute the slope of

y = x^{2} - 5 x + 5 \cdot 0.5

x = a_{0} : m = 2 a_{0} - 5

Find the line with slope m=

2 a_{0} - 5

and passing through

(a_{0}, a_{0}^{2} - 5 a_{0} + 2.5) : y = (2 a_{0} - 5) x - a_{0}^{2} + 2.5

y = (2 a_{0} - 5) x - a_{0}^{2} + 2.5

F (s) = ln (ln (6 s))

\int_{0}^{\frac{π}{2}} sec (x) d x

t \to 0 lim (\frac{tan ( 10 t )}{sin ( 2 t )})

\frac{d}{d x} (x \cdot e^{3 x})

\int \frac{1}{6 - x} d x

What is the tangent of y=x^2-5x+5(0.5) ?
The tangent of y=x^2-5x+5(0.5) is y=(2a_{0}-5)x-a_{0}^2+2.5