What is the integral from-8 to 8 of 1/(\sqrt[3]{x)} ?

The integral from-8 to 8 of 1/(\sqrt[3]{x)} is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-8 to 8 of 1/(\sqrt[3]{x)}

0

Solution steps

Find undefined (singularity) points:

x = 0

If exist

b, a < b < c, f (b) =

undefined

, \int_{a}^{c} f (x) d x = \int_{a}^{b} f (x) d x + \int_{b}^{c} f (x) d x

= - 6 (- 1)^{\frac{2}{3}} + 6

Simplify

- 6 (- 1)^{\frac{2}{3}} + 6 : 0

= 0

\frac{d y}{d x}, y = 7 x^{8}

\int 3 x - 4 x d x

x \to 3 - lim (\frac{2 x}{x - 3})

x \to 3 lim (lo g_{5} (x))

\frac{d}{d x} (x + y)

What is the integral from-8 to 8 of 1/(\sqrt[3]{x)} ?
The integral from-8 to 8 of 1/(\sqrt[3]{x)} is 0