What is the derivative of x+sqrt(y) ?

The derivative of x+sqrt(y) is 1+(\frac{dy)/(dx)}{2sqrt(y)}

What is the first derivative of x+sqrt(y) ?

The first derivative of x+sqrt(y) is 1+(\frac{dy)/(dx)}{2sqrt(y)}

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\frac{d}{d x} (x + y)

1 + \frac{\frac{d y}{d x}}{2 y}

Solution steps

\frac{d}{d x} (x + y)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} + \frac{d}{d x} (y)

\frac{d x}{d x} = 1

\frac{d}{d x} (y) = \frac{\frac{d y}{d x}}{2 y}

= 1 + \frac{\frac{d y}{d x}}{2 y}

sin (t)

x \to 0 + lim (e^{x})

\frac{d ^{2}}{d x ^{2}} ((4 x^{2} + 2 x) sin (x))

(- 2, 2), (2, - 1)

\frac{d}{d x} (3 x^{4} - 16 x^{3} + 18 x^{2})

What is the derivative of x+sqrt(y) ?
The derivative of x+sqrt(y) is 1+(\frac{dy)/(dx)}{2sqrt(y)}
What is the first derivative of x+sqrt(y) ?
The first derivative of x+sqrt(y) is 1+(\frac{dy)/(dx)}{2sqrt(y)}