What is the sum from n=1 to infinity of n/(5^n) ?

The sum from n=1 to infinity of n/(5^n) is converges

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sum from n=1 to infinity of n/(5^n)

n = 1 \sum \infty \frac{n}{5 ^{n}}

converges

Solution steps

n = 1 \sum \infty \frac{n}{5 ^{n}}

Apply Series Ratio Test:

converges

= converges

\frac{\partial}{\partial x} (x^{2} + x y - 10)

\frac{d}{d x} (2 x^{3} cos (x) sin (x))

n = 0 \sum \infty \frac{( - 1 ) ^{n}}{2}

t \to 0 lim (\frac{e ^{7 t} - 1}{sin ( t )})

\frac{\partial}{\partial x} (3 x + 7)

What is the sum from n=1 to infinity of n/(5^n) ?
The sum from n=1 to infinity of n/(5^n) is converges