What is the integral from 1 to 2 of (1/x) ?

The integral from 1 to 2 of (1/x) is ln(2)

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integral from 1 to 2 of (1/x)

\int_{1}^{2} (\frac{1}{x}) d x

ln (2)

Decimal Notation

0.69314 \dots

Solution steps

\int_{1}^{2} \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= [ln ∣ x ∣]_{1}^{2}

Compute the boundaries:

ln (2)

= ln (2)

\int \frac{sin ( 2 x )}{11 + cos ^{2} ( x )} d x

\int tan^{3} (x) \cdot sec (x) d x

\frac{\partial}{\partial x} (cos (x^{2} \cdot y))

h \to 0 lim (\frac{4 ^{h} - 1}{h})

x \to \frac{13 π}{3} lim (cos (x))

What is the integral from 1 to 2 of (1/x) ?
The integral from 1 to 2 of (1/x) is ln(2)