What is the tangent of y=xsqrt(x),(9,27) ?

The tangent of y=xsqrt(x),(9,27) is y= 9/2 x-27/2

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tangent of y=xsqrt(x),(9,27)

tangent of

y = x x, (9, 27)

y = \frac{9}{2} x - \frac{27}{2}

Solution steps

Find the slope of

y = x x : \frac{d y}{d x} = \frac{3 x}{2}

Compute the slope of

y = x x

(9, 27) : m = \frac{9}{2}

Find the line with slope m=

\frac{9}{2}

and passing through

(9, 27) : y = \frac{9}{2} x - \frac{27}{2}

y = \frac{9}{2} x - \frac{27}{2}

\frac{d}{d n} (5^{n})

x \to 4 lim (\frac{8}{x})

\int \frac{1}{x ^{2} + 2 x + 5} d x

y = 6 + 4 x^{2} - 2 x^{3}

\int_{1}^{\infty} 2 e^{- x} d x

What is the tangent of y=xsqrt(x),(9,27) ?
The tangent of y=xsqrt(x),(9,27) is y= 9/2 x-27/2