What is the tangent of f(x)= 2/x ,\at x=-9 ?

The tangent of f(x)= 2/x ,\at x=-9 is y=-2/81 x-4/9

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tangent of f(x)= 2/x ,\at x=-9

tangent of

f (x) = \frac{2}{x}, at x = - 9

y = - \frac{2}{81} x - \frac{4}{9}

Solution steps

Find the tangent point:

(- 9, - \frac{2}{9})

Find the slope of

f (x) = \frac{2}{x} : \frac{df ( x )}{d x} = - \frac{2}{x ^{2}}

Compute the slope of

f (x) = \frac{2}{x}

x = - 9 : m = - \frac{2}{81}

Find the line with slope m=

- \frac{2}{81}

and passing through

(- 9, - \frac{2}{9}) : y = - \frac{2}{81} x - \frac{4}{9}

y = - \frac{2}{81} x - \frac{4}{9}

\frac{d}{d x} ((x^{2} + 2 x) e^{x})

\int_{- 1}^{1} cos (nπ x) d x

x^{2} + 2 x y - y^{2} + x = 51, (5, 7)

(4.3) (4.6)

\int e^{- x} + e^{- 3 x} d x

What is the tangent of f(x)= 2/x ,\at x=-9 ?
The tangent of f(x)= 2/x ,\at x=-9 is y=-2/81 x-4/9