What is the tangent of y= 2/x ,(-3,-2/3) ?

The tangent of y= 2/x ,(-3,-2/3) is y=-2/9 x-4/3

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tangent of y= 2/x ,(-3,-2/3)

tangent of

y = \frac{2}{x}, (- 3, - \frac{2}{3})

y = - \frac{2}{9} x - \frac{4}{3}

Solution steps

Find the slope of

y = \frac{2}{x} : \frac{d y}{d x} = - \frac{2}{x ^{2}}

Compute the slope of

y = \frac{2}{x}

(- 3, - \frac{2}{3}) : m = - \frac{2}{9}

Find the line with slope m=

- \frac{2}{9}

and passing through

(- 3, - \frac{2}{3}) : y = - \frac{2}{9} x - \frac{4}{3}

y = - \frac{2}{9} x - \frac{4}{3}

\frac{d}{d x} (- x^{3} + 3 x^{2} + 4)

y^{^{'}} y^{^{''}} = 2

e^{- 2 t} (3 t)^{2}

\frac{d}{d x} ((f (x) (3 x))^{2} + 5)

x \to 2 lim (5 x^{2} - 3 x + 1)

What is the tangent of y= 2/x ,(-3,-2/3) ?
The tangent of y= 2/x ,(-3,-2/3) is y=-2/9 x-4/3