What is the solution for y^'+2xy+xy^4=0 ?

The solution for y^'+2xy+xy^4=0 is y=\sqrt[3]{2/(e^{3x^2-c_{1)}-1}}

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y^'+2xy+xy^4=0

y^{^{'}} + 2 x y + x y^{4} = 0

Solution steps

y^{'} (x) + 2 x y + x y^{4} = 0

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What is the solution for y^'+2xy+xy^4=0 ?
The solution for y^'+2xy+xy^4=0 is y=\sqrt[3]{2/(e^{3x^2-c_{1)}-1}}