What is the solution for (dy)/(dx)=2^{x-y},y(-3)=-5 ?

The solution for (dy)/(dx)=2^{x-y},y(-3)=-5 is y=(ln(2^x-3/32))/(ln(2))

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(dy)/(dx)=2^{x-y},y(-3)=-5

\frac{d y}{d x} = 2^{x - y}, y (- 3) = - 5

y = \frac{ln ( 2 ^{x} - \frac{3}{32} )}{ln ( 2 )}

Solution steps

\frac{d y}{d x} = 2^{x - y}

Solve separable ODE:

y = \frac{ln ( 2 ^{x} - \frac{3}{32} )}{ln ( 2 )}

y = \frac{ln ( 2 ^{x} - \frac{3}{32} )}{ln ( 2 )}

\int \frac{4 x + 8}{( x + 5 ) ^{2}} d x

\frac{1}{4 x ^{\frac{3}{4}}}

(- 7.4) (- 4.1)

- sin (x)

(\frac{2}{2 s + 1}) - (\frac{1}{s})

What is the solution for (dy)/(dx)=2^{x-y},y(-3)=-5 ?
The solution for (dy)/(dx)=2^{x-y},y(-3)=-5 is y=(ln(2^x-3/32))/(ln(2))