What is the solution for 6y^'+ty=7 ?

The solution for 6y^'+ty=7 is y=(integral of (7e^{\frac{t^2)/(12)})/6}{e^{(t^2)/(12)}}

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6y^'+ty=7

6 y^{^{'}} + t y = 7

y = \frac{\int \frac{7 e ^{\frac{t ^{2}}{12}}}{6} d t}{e ^{\frac{t ^{2}}{12}}}

Solution steps

6 y^{'} (t) + t y = 7

Solve linear ODE:

y = \frac{\int \frac{7 e ^{\frac{t ^{2}}{12}}}{6} d t}{e ^{\frac{t ^{2}}{12}}}

y = \frac{\int \frac{7 e ^{\frac{t ^{2}}{12}}}{6} d t}{e ^{\frac{t ^{2}}{12}}}

\int_{- 2}^{2} x^{4} d x

3 x ln (6 x) - 3 x

\int \frac{1}{2} x e^{x} d x

x \to - 1 lim (x^{2} - 4 + (x^{2} - 9)^{\frac{1}{3}})

n = 0 \sum \infty n (n - 1) x^{n}

What is the solution for 6y^'+ty=7 ?
The solution for 6y^'+ty=7 is y=(integral of (7e^{\frac{t^2)/(12)})/6}{e^{(t^2)/(12)}}