What is the derivative of ((e^x))/(9x^2) ?

The derivative of ((e^x))/(9x^2) is (e^x(x-2))/(9x^3)

What is the first derivative of ((e^x))/(9x^2) ?

The first derivative of ((e^x))/(9x^2) is (e^x(x-2))/(9x^3)

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derivative of

\frac{( e ^{x} )}{9 x ^{2}}

\frac{e ^{x} ( x - 2 )}{9 x ^{3}}

Solution steps

\frac{d}{d x} (\frac{e ^{x}}{9 x ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{9} \frac{d}{d x} (\frac{e ^{x}}{x ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{1}{9} \cdot \frac{\frac{d}{d x} ( e ^{x} ) x ^{2} - \frac{d}{d x} ( x ^{2} ) e ^{x}}{( x ^{2} ) ^{2}}

\frac{d}{d x} (e^{x}) = e^{x}

\frac{d}{d x} (x^{2}) = 2 x

= \frac{1}{9} \cdot \frac{e ^{x} x ^{2} - 2 x e ^{x}}{( x ^{2} ) ^{2}}

Simplify

\frac{1}{9} \cdot \frac{e ^{x} x ^{2} - 2 x e ^{x}}{( x ^{2} ) ^{2}} : \frac{e ^{x} ( x - 2 )}{9 x ^{3}}

= \frac{e ^{x} ( x - 2 )}{9 x ^{3}}

x y^{^{'}} - 2 y = 2 x^{2} + x + 2

\int x^{3} (x + 1) d x

x \to o lim (2 x - 1)

\int \frac{3}{4} x d x

\frac{\partial}{\partial z} (e^{x y} - z)

What is the derivative of ((e^x))/(9x^2) ?
The derivative of ((e^x))/(9x^2) is (e^x(x-2))/(9x^3)
What is the first derivative of ((e^x))/(9x^2) ?
The first derivative of ((e^x))/(9x^2) is (e^x(x-2))/(9x^3)