What is the derivative of sec(1+x^2) ?

The derivative of sec(1+x^2) is sec(1+x^2)tan(1+x^2)*2x

What is the first derivative of sec(1+x^2) ?

The first derivative of sec(1+x^2) is sec(1+x^2)tan(1+x^2)*2x

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\frac{d}{d x} (sec (1 + x^{2}))

sec (1 + x^{2}) tan (1 + x^{2}) \cdot 2 x

Solution steps

\frac{d}{d x} (sec (1 + x^{2}))

Apply the chain rule:

sec (1 + x^{2}) tan (1 + x^{2}) \frac{d}{d x} (1 + x^{2})

= sec (1 + x^{2}) tan (1 + x^{2}) \frac{d}{d x} (1 + x^{2})

\frac{d}{d x} (1 + x^{2}) = 2 x

= sec (1 + x^{2}) tan (1 + x^{2}) \cdot 2 x

\int \frac{63}{1 - cos ( 7 x )} d x

\int e^{- 5 x} cos (x) d x

\frac{\partial}{\partial y} (3 x^{2} + 2 y^{2})

(y + 1) d x + (y - 1) (1 + x^{2}) d y = 0

\frac{\partial}{\partial y} (- 3 y^{4} sin (3 x))

What is the derivative of sec(1+x^2) ?
The derivative of sec(1+x^2) is sec(1+x^2)tan(1+x^2)*2x
What is the first derivative of sec(1+x^2) ?
The first derivative of sec(1+x^2) is sec(1+x^2)tan(1+x^2)*2x