What is the solution for (dx)/(dy)=(2y+sec^2(y))/(2x) ?

The solution for (dx)/(dy)=(2y+sec^2(y))/(2x) is x=sqrt(y^2+tan(y)+c_{1)},x=-sqrt(y^2+tan(y)+c_{1)}

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(dx)/(dy)=(2y+sec^2(y))/(2x)

\frac{d x}{d y} = \frac{2 y + sec ^{2} ( y )}{2 x}

x = y^{2} + tan (y) + c_{1}, x = - y^{2} + tan (y) + c_{1}

Solution steps

\frac{d x}{d y} = \frac{2 y + sec ^{2} ( y )}{2 x}

Solve separable ODE:

x = y^{2} + tan (y) + c_{1}, x = - y^{2} + tan (y) + c_{1}

x = y^{2} + tan (y) + c_{1}, x = - y^{2} + tan (y) + c_{1}

(3 e^{x})^{^{'}}

\int_{0}^{0.5} 250 x d x

f (x) = \frac{x ^{3}}{3} + 6 x^{2} + 36 x + 9

\int \frac{x}{1 + 2 x} d x

\frac{d}{d x} (- (x + 3) (x - 9)^{2})

What is the solution for (dx)/(dy)=(2y+sec^2(y))/(2x) ?
The solution for (dx)/(dy)=(2y+sec^2(y))/(2x) is x=sqrt(y^2+tan(y)+c_{1)},x=-sqrt(y^2+tan(y)+c_{1)}