What is the tangent of f(x)=sqrt(5x+6),(2,4) ?

The tangent of f(x)=sqrt(5x+6),(2,4) is y= 5/8 x+11/4

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tangent of f(x)=sqrt(5x+6),(2,4)

tangent of

f (x) = 5 x + 6, (2, 4)

y = \frac{5}{8} x + \frac{11}{4}

Solution steps

Find the slope of

f (x) = 5 x + 6 : \frac{df ( x )}{d x} = \frac{5}{2 5 x + 6}

Compute the slope of

f (x) = 5 x + 6

(2, 4) : m = \frac{5}{8}

Find the line with slope m=

\frac{5}{8}

and passing through

(2, 4) : y = \frac{5}{8} x + \frac{11}{4}

y = \frac{5}{8} x + \frac{11}{4}

t \cdot sin (t)

\frac{d}{d x} (sin (2 x) + 3 ln (e) + 4 x)

(4, 2), (3, - 1)

\frac{\partial}{\partial θ} (cos^{2} (θ))

\int (cos (θ))^{3} d θ

What is the tangent of f(x)=sqrt(5x+6),(2,4) ?
The tangent of f(x)=sqrt(5x+6),(2,4) is y= 5/8 x+11/4