What is the derivative of-131072sin(2x) ?

The derivative of-131072sin(2x) is -262144cos(2x)

What is the first derivative of-131072sin(2x) ?

The first derivative of-131072sin(2x) is -262144cos(2x)

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\frac{d}{d x} (- 131072 sin (2 x))

- 262144 cos (2 x)

Solution steps

\frac{d}{d x} (- 131072 sin (2 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 131072 \frac{d}{d x} (sin (2 x))

Apply the chain rule:

cos (2 x) \frac{d}{d x} (2 x)

= cos (2 x) \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= - 131072 cos (2 x) \cdot 2

Simplify

= - 262144 cos (2 x)

x \to (- 1^{+}) lim (4 x^{3} - 2 m)

ln (3 x^{3} + 2)

\frac{\partial}{\partial r} (2 t + r^{2} cos (t))

\int \frac{e ^{4 x}}{1 + e ^{2 x}} d x

\int_{0}^{\infty} \frac{x}{e ^{x}} d x

What is the derivative of-131072sin(2x) ?
The derivative of-131072sin(2x) is -262144cos(2x)
What is the first derivative of-131072sin(2x) ?
The first derivative of-131072sin(2x) is -262144cos(2x)