What is the tangent of y=6tan(x),\at x= pi/6 ?

The tangent of y=6tan(x),\at x= pi/6 is y=8x+2sqrt(3)-(4pi)/3

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tangent of y=6tan(x),\at x= pi/6

tangent of

y = 6 tan (x), at x = \frac{π}{6}

y = 8 x + 23 - \frac{4 π}{3}

Solution steps

Find the tangent point:

(\frac{π}{6}, 23)

Find the slope of

y = 6 tan (x) : \frac{d y}{d x} = 6 sec^{2} (x)

Compute the slope of

y = 6 tan (x)

x = \frac{π}{6} : m = 8

Find the line with slope m=

8

and passing through

(\frac{π}{6}, 23) : y = 8 x + 23 - \frac{4 π}{3}

y = 8 x + 23 - \frac{4 π}{3}

\frac{\partial}{\partial x} (x^{y} + ln (z))

n = 1 \sum \infty \frac{5}{n ^{3}}

sec (x) \frac{d y}{d x} = e^{y + s i n (x)}

\int \frac{x}{x ^{2} + 7} d x

\frac{\partial}{\partial x} (- 4 x^{2})

What is the tangent of y=6tan(x),\at x= pi/6 ?
The tangent of y=6tan(x),\at x= pi/6 is y=8x+2sqrt(3)-(4pi)/3