What is the derivative of 4x^2+1/x ?

The derivative of 4x^2+1/x is 8x-1/(x^2)

What is the first derivative of 4x^2+1/x ?

The first derivative of 4x^2+1/x is 8x-1/(x^2)

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\frac{d}{d x} (4 x^{2} + \frac{1}{x})

8 x - \frac{1}{x ^{2}}

Solution steps

\frac{d}{d x} (4 x^{2} + \frac{1}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{2}) + \frac{d}{d x} (\frac{1}{x})

\frac{d}{d x} (4 x^{2}) = 8 x

\frac{d}{d x} (\frac{1}{x}) = - \frac{1}{x ^{2}}

= 8 x - \frac{1}{x ^{2}}

y = \frac{5 + sin ( x )}{5 x + cos ( x )}

f (x) = \frac{1}{4 + 3 x}, (2, \frac{1}{10})

- 4 e^{t}

e^{x} y^{^{'}} = e^{- y} + e^{2 x - y}

\frac{1}{x - 1}, 19

What is the derivative of 4x^2+1/x ?
The derivative of 4x^2+1/x is 8x-1/(x^2)
What is the first derivative of 4x^2+1/x ?
The first derivative of 4x^2+1/x is 8x-1/(x^2)