What is the limit as x approaches 0 of ln(e^x-1) ?

The limit as x approaches 0 of ln(e^x-1) is Does not exist

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limit as x approaches 0 of ln(e^x-1)

x \to 0 lim (ln (e^{x} - 1))

Does not exist

Solution steps

x \to 0 lim (ln (e^{x} - 1))

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (ln (e^{x} - 1)) = - \infty

x \to 0 - lim (ln (e^{x} - 1)) =

Does not exist

= Does not exist

\frac{1}{( x - 1 )}, at x = 2

x \to 1 + lim (\frac{x}{x ^{2} - 1})

\frac{\partial}{\partial v} ((u^{2} v - v^{3})^{5})

(- 3, 0), (0, - 3)

\frac{d}{d x} (x \cdot cos^{3} (4 x))

What is the limit as x approaches 0 of ln(e^x-1) ?
The limit as x approaches 0 of ln(e^x-1) is Does not exist