What is the limit as x approaches 1+of x/(x^2-1) ?

The limit as x approaches 1+of x/(x^2-1) is infinity

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 1+of x/(x^2-1)

x \to 1 + lim (\frac{x}{x ^{2} - 1})

\infty

Solution steps

x \to 1 + lim (\frac{x}{x ^{2} - 1})

\frac{x}{x ^{2} - 1} = x \frac{1}{x ^{2} - 1}

= x \to 1 + lim (x \frac{1}{x ^{2} - 1})

x \to a lim [f (x) \cdot g (x)] = x \to a lim f (x) \cdot x \to a lim g (x)

With the exception of indeterminate form

= x \to 1 + lim (x) \cdot x \to 1 + lim (\frac{1}{x ^{2} - 1})

x \to 1 + lim (x) = 1

x \to 1 + lim (\frac{1}{x ^{2} - 1}) = \infty

= 1 \cdot \infty

Apply Infinity Property:

c \cdot \infty = \infty

= \infty

\frac{\partial}{\partial v} ((u^{2} v - v^{3})^{5})

(- 3, 0), (0, - 3)

\frac{d}{d x} (x \cdot cos^{3} (4 x))

\frac{d}{d x} (x^{4} + e^{- x})

x \to 0 lim (2 x + 4)

What is the limit as x approaches 1+of x/(x^2-1) ?
The limit as x approaches 1+of x/(x^2-1) is infinity