What is the derivative of (3x^2+2/4) ?

The derivative of (3x^2+2/4) is (3x)/2

What is the first derivative of (3x^2+2/4) ?

The first derivative of (3x^2+2/4) is (3x)/2

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\frac{d}{d x} (\frac{3 x ^{2} + 2}{4})

\frac{3 x}{2}

Solution steps

\frac{d}{d x} (\frac{3 x ^{2} + 2}{4})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{4} \frac{d}{d x} (3 x^{2} + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{4} (\frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (2))

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (2) = 0

= \frac{1}{4} (6 x + 0)

Simplify

\frac{1}{4} (6 x + 0) : \frac{3 x}{2}

= \frac{3 x}{2}

\frac{\partial}{\partial x} (8 x^{2} + 4 y)

\int (x^{5} + 2)^{2} d x

\int_{0}^{2} 9 e^{- 2 x} d x

n = k \sum \infty \frac{1}{2 ^{n}}

\int \frac{1}{( 1 - x ^{2} ) ^{2}} d x

What is the derivative of (3x^2+2/4) ?
The derivative of (3x^2+2/4) is (3x)/2
What is the first derivative of (3x^2+2/4) ?
The first derivative of (3x^2+2/4) is (3x)/2