What is the tangent of y=3x-2sqrt(x),(1,1) ?

The tangent of y=3x-2sqrt(x),(1,1) is y=2x-1

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tangent of y=3x-2sqrt(x),(1,1)

tangent of

y = 3 x - 2 x, (1, 1)

y = 2 x - 1

Solution steps

Find the slope of

y = 3 x - 2 x : \frac{d y}{d x} = 3 - \frac{1}{x}

Compute the slope of

y = 3 x - 2 x

(1, 1) : m = 2

Find the line with slope m=

2

and passing through

(1, 1) : y = 2 x - 1

y = 2 x - 1

(2 e^{y} - x) \frac{d y}{d x} = 1

\frac{d}{d x} ((7 + x)^{5})

x \to - 0 lim (ln (x))

y = \frac{x ^{2} + 32 x}{8}, x = 4

\frac{2}{s ^{3} ( s ^{2} - 9 )}

What is the tangent of y=3x-2sqrt(x),(1,1) ?
The tangent of y=3x-2sqrt(x),(1,1) is y=2x-1