What is the integral of 3/(4x) ?

The integral of 3/(4x) is 3/4 ln|x|+C

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integral of 3/(4x)

\int \frac{3}{4 x} d x

\frac{3}{4} ln ∣ x ∣ + C

Solution steps

\int \frac{3}{4 x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{3}{4} \cdot \int \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= \frac{3}{4} ln ∣ x ∣

Add a constant to the solution

= \frac{3}{4} ln ∣ x ∣ + C

x^{2} - 4 x + 2

n = 0 \sum \infty \frac{1}{n ( n - 1 )}

\frac{1}{2 r} + \frac{1}{7 r ^{\frac{6}{7}}}

f (x) = \frac{x ^{2} + 11 x + 24}{x + 8}

\frac{d x}{d t} = x