What is the derivative of y=arccot(sqrt(2t)) ?

The derivative of y=arccot(sqrt(2t)) is -1/(sqrt(2)\sqrt{t)(2t+1)}

What is the first derivative of y=arccot(sqrt(2t)) ?

The first derivative of y=arccot(sqrt(2t)) is -1/(sqrt(2)\sqrt{t)(2t+1)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

y = arccot (2 t)

- \frac{1}{2 t ( 2 t + 1 )}

Solution steps

\frac{d}{d t} (arccot (2 t))

Simplify

arccot (2 t) : arccot (2 t)

= \frac{d}{d t} (arccot (2 t))

Apply the chain rule:

- \frac{1}{( 2 t ) ^{2} + 1} \frac{d}{d t} (2 t)

= - \frac{1}{( 2 t ) ^{2} + 1} \frac{d}{d t} (2 t)

\frac{d}{d t} (2 t) = \frac{1}{2 t}

= - \frac{1}{( 2 t ) ^{2} + 1} \cdot \frac{1}{2 t}

Simplify

- \frac{1}{( 2 t ) ^{2} + 1} \cdot \frac{1}{2 t} : - \frac{1}{2 t ( 2 t + 1 )}

= - \frac{1}{2 t ( 2 t + 1 )}

\int \frac{4 x ^{2}}{( 16 + x ^{2} ) ^{2}} d x

y^{^{''}} - 6 y^{^{'}} - 7 y = 15 e^{2 t}

\int - \frac{5}{x ^{2}} d x

\frac{d y}{d x} + y = 2 x

What is the derivative of y=arccot(sqrt(2t)) ?
The derivative of y=arccot(sqrt(2t)) is -1/(sqrt(2)\sqrt{t)(2t+1)}
What is the first derivative of y=arccot(sqrt(2t)) ?
The first derivative of y=arccot(sqrt(2t)) is -1/(sqrt(2)\sqrt{t)(2t+1)}