What is the solution for (dy)/(dx)-1/x y=e^{(y/x)} ?

The solution for (dy)/(dx)-1/x y=e^{(y/x)} is y=-xln(-ln(x)-c_{1})

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)-1/x y=e^{(y/x)}

\frac{d y}{d x} - \frac{1}{x} y = e^{(\frac{y}{x})}

y = - x ln (- ln (x) - c_{1})

Solution steps

\frac{d y}{d x} - \frac{1}{x} y = e^{(\frac{y}{x})}

Solve using substitution:

y = - x ln (- ln (x) - c_{1})

y = - x ln (- ln (x) - c_{1})

x \to π lim ((x - π) tan (\frac{x}{2}))

\frac{\partial}{\partial x} (x y + yz + zy)

n = 0 \sum \infty \frac{3 ^{n}}{5 ^{n}}

y = 6 sin (x), at x = \frac{π}{6}

\frac{\partial}{\partial y} (x y - \frac{x ^{4}}{4})

What is the solution for (dy)/(dx)-1/x y=e^{(y/x)} ?
The solution for (dy)/(dx)-1/x y=e^{(y/x)} is y=-xln(-ln(x)-c_{1})