What is the tangent of y=6sin(x),\at x= pi/6 ?

The tangent of y=6sin(x),\at x= pi/6 is y=3sqrt(3)x+3-(sqrt(3)pi)/2

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tangent of y=6sin(x),\at x= pi/6

tangent of

y = 6 sin (x), at x = \frac{π}{6}

y = 33 x + 3 - \frac{3 π}{2}

Solution steps

Find the tangent point:

(\frac{π}{6}, 3)

Find the slope of

y = 6 sin (x) : \frac{d y}{d x} = 6 cos (x)

Compute the slope of

y = 6 sin (x)

x = \frac{π}{6} : m = 33

Find the line with slope m=

33

and passing through

(\frac{π}{6}, 3) : y = 33 x + 3 - \frac{3 π}{2}

y = 33 x + 3 - \frac{3 π}{2}

\frac{\partial}{\partial y} (x y - \frac{x ^{4}}{4})

\int e^{- 2 x} sin (6 x) d x

\frac{d}{d x} (x^{6} e^{2.5 x})

\frac{d}{d x} (e^{- 0.02 x})

18 e^{x^{2}} x

What is the tangent of y=6sin(x),\at x= pi/6 ?
The tangent of y=6sin(x),\at x= pi/6 is y=3sqrt(3)x+3-(sqrt(3)pi)/2