What is the derivative of f(x)=x^2+6 ?

The derivative of f(x)=x^2+6 is 2x

What is the first derivative of f(x)=x^2+6 ?

The first derivative of f(x)=x^2+6 is 2x

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derivative of

f (x) = x^{2} + 6

2 x

Solution steps

\frac{d}{d x} (x^{2} + 6)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (6)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (6) = 0

= 2 x + 0

Simplify

= 2 x

y^{^{''}} - 7 y^{^{'}} = 2 t

\int \frac{5}{25 x ^{2} - 9} d x

- 2 x^{2} + 8, - x - 6

\int \frac{x ^{3} - 2 x ^{2} - 4}{x ^{3} - 2 x ^{2}} d x

\int \frac{x ^{4} + 2}{x ^{3} + 9 x} d x

What is the derivative of f(x)=x^2+6 ?
The derivative of f(x)=x^2+6 is 2x
What is the first derivative of f(x)=x^2+6 ?
The first derivative of f(x)=x^2+6 is 2x