What is the derivative of-1.8t^2+14.4t ?

The derivative of-1.8t^2+14.4t is -3.6t+14.4

What is the first derivative of-1.8t^2+14.4t ?

The first derivative of-1.8t^2+14.4t is -3.6t+14.4

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derivative of

- 1.8 t^{2} + 14.4 t

- 3.6 t + 14.4

Solution steps

\frac{d}{d t} (- 1.8 t^{2} + 14.4 t)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d t} (1.8 t^{2}) + \frac{d}{d t} (14.4 t)

\frac{d}{d t} (1.8 t^{2}) = 3.6 t

\frac{d}{d t} (14.4 t) = 14.4

= - 3.6 t + 14.4

y = t sin (t) + cos (t)

\int 9 ln (x) d x

\frac{- x ^{2} - 2}{( x ^{2} - 2 ) ^{2}}

\frac{\partial}{\partial x} (2 x - x^{3} + 3 x y^{2})

ln (cos (x))

What is the derivative of-1.8t^2+14.4t ?
The derivative of-1.8t^2+14.4t is -3.6t+14.4
What is the first derivative of-1.8t^2+14.4t ?
The first derivative of-1.8t^2+14.4t is -3.6t+14.4