What is the derivative of (-x^2-2)/((x^2-2)^2) ?

The derivative of (-x^2-2)/((x^2-2)^2) is -(2x(-x^2-6))/((x^2-2)^3)

What is the first derivative of (-x^2-2)/((x^2-2)^2) ?

The first derivative of (-x^2-2)/((x^2-2)^2) is -(2x(-x^2-6))/((x^2-2)^3)

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derivative of

\frac{- x ^{2} - 2}{( x ^{2} - 2 ) ^{2}}

- \frac{2 x ( - x ^{2} - 6 )}{( x ^{2} - 2 ) ^{3}}

Solution steps

\frac{d}{d x} (\frac{- x ^{2} - 2}{( x ^{2} - 2 ) ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( - x ^{2} - 2 ) ( x ^{2} - 2 ) ^{2} - \frac{d}{d x} ( ( x ^{2} - 2 ) ^{2} ) ( - x ^{2} - 2 )}{( ( x ^{2} - 2 ) ^{2} ) ^{2}}

\frac{d}{d x} (- x^{2} - 2) = - 2 x

\frac{d}{d x} ((x^{2} - 2)^{2}) = 4 x (x^{2} - 2)

= \frac{( - 2 x ) ( x ^{2} - 2 ) ^{2} - 4 x ( x ^{2} - 2 ) ( - x ^{2} - 2 )}{( ( x ^{2} - 2 ) ^{2} ) ^{2}}

Simplify

\frac{( - 2 x ) ( x ^{2} - 2 ) ^{2} - 4 x ( x ^{2} - 2 ) ( - x ^{2} - 2 )}{( ( x ^{2} - 2 ) ^{2} ) ^{2}} : - \frac{2 x ( - x ^{2} - 6 )}{( x ^{2} - 2 ) ^{3}}

= - \frac{2 x ( - x ^{2} - 6 )}{( x ^{2} - 2 ) ^{3}}

\frac{\partial}{\partial x} (2 x - x^{3} + 3 x y^{2})

ln (cos (x))

\frac{d y}{d x} = \frac{x}{36 y}

\frac{8}{s ^{2} + 64}

\int (4 x^{3} + 6 x^{2} - 1) d x

What is the derivative of (-x^2-2)/((x^2-2)^2) ?
The derivative of (-x^2-2)/((x^2-2)^2) is -(2x(-x^2-6))/((x^2-2)^3)
What is the first derivative of (-x^2-2)/((x^2-2)^2) ?
The first derivative of (-x^2-2)/((x^2-2)^2) is -(2x(-x^2-6))/((x^2-2)^3)